Python 每日一练：等分字符串

from textwrap import wrap

# 'F0-B4-29-98-CE-34'
'-'.join(wrap('F0B42998CE34', 2))

@krixaar 嗯嗯，多谢哈。

'-'.join(s[x:x+2] for x in range(0, len(s), 2))

@krixaar #1 学到老活到老

好答案前面有了，我再多贡献一条基于正则的花活。若干年前学自《精通正则表达式》，对于当时的我过于震撼，牢记至今：

>>> s = 'F0B42998CE34'
>>> import re
>>> re.sub(r'(?<=.)(?=(..)+$)', '-', s)
'F0-B4-29-98-CE-34'

string='20220202'
# out put-> 2022-02-02
楼下的请解答

''.join([(str[i]+('-' if i%2 and not (i==1 or i == len(str)-1) else '')) for i in range(len(str))])

```python

s = 'F0B42998CE34'

def chunk(iterable, chunk_size, on_chunk=None):
on_chunk = on_chunk or (lambda x:x)
return [on_chunk(chunk) for chunk in zip(*[iter(iterable)] * chunk_size)]

res = chunk(s,2,''.join)
print('-'.join(res))



```
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